Wednesday, January 26, 2011

Wednesday, January 26, 2011

Announcements : -If you have any questions about moles find Mr. Paek ( he is free 5th and 6th period.) This is a really important unit and if you want to do good on the test you have to do good on the quizzes.
-Make sure to show all work and units in homework and quizzes, because it will get very confusing later on if you don't get in the habit of doing it right now.
- Buy a notebook if you haven't already.
- First quiz tomorrow/ 7 quizzes total this unit.
Homework: -pages 7-8.
Body: Today in class we went over some problems from pages 1-6.(Again: make sure that you go get help from the TLC or Mr. Paek if you don't get something.) Then we did a lab called: Moles Stations Lab. The lab had 9 stations, and in each one of them we calculated either the mass number, mole, or the number of atoms.
Set1: had to count the number of pairs of shoes in the room.
Set2:find the mass of Aluminum foil and find its mass number and how many moles it had.
Set3:find the mass of a carbon rod find mass number of it and how moles, then how many atoms.
Set 4:we had to find how many moles of Krypton in a graduated cylinder, and the mass of it.
Set 5:we had to find the mass of H2O, and the number of grams in one mole of H2O.
Set 6:find one mole of HCl, the number of moles in it, and the number of molecules.
Set 7:found the volume of an aluminum bar its density and the number of moles and atoms.
Set 8:find the mass if neon, and the number of atoms in it.
Set 9:find the mass of a balloon and the balloon's mole.
***examples from some problems in the lab:***
set 2: 1)The mass of Aluminum foil=3.74g
2) The mass from the periodic table = 27 g/mole
3)Number of moles Aluminum foil has=3.74 g Al foil*1mole/27g of Al foil=0.14 moles of Al.
set3: 1) Mass of carbon rod= 4.35 g
2)Mass from periodic table= 12 g/mole
3)Number of mole in this carbon rod= 4.35g carbon rod* 1mole/12 g carbon rod=.36moles
4)Number of atoms in rod=.36mol*6.02E23atoms of carbon/1mole=2.16E24 atoms of carbon




No comments:

Post a Comment