Wednesday, March 16, 2011
3.15.11
Thursday, January 27, 2011
Wednesday, January 26, 2011
Wednesday, January 26, 2011
Tuesday, January 25, 2011
Tuesday, January 25, 2011
Monday, January 24, 2011
1/24/11
Today In Class- Today in class, after rejoining us to the class again and welcoming any new students, we were introduced to the mol. A mol is 6.02 x 10 to the 23rd power. We were also told that a pair=2 and a dozen=12. Then we did a lab that worked on using Unit Analysis for finding the number of atoms in a certain number of grams, the number of grams in a certain number of mols, and the number of mols in a certain number of grams. An example of a question for finding the number of grams would be: How many grams would 3.01 x 1023 atoms of Al (26.98 grams) be? 3.o1 x 1023 atoms x 26.98 g
6.02 x 1023 atoms
Then you would cancel out atoms and do the math.
Homework- Finish the lab. We're going over it in class if you have any questions.
THE NEXT SCRIBER WILL BE....... paul mcmahon
Wednesday, December 8, 2010
12/8/10
- Quiz tomorrow on balancing
- Possibly a quiz on Friday so be ready
- Test on the last Thursday before break
What We Did In Class
Today in class we first went over the homework we had the night before, which was pages 8 and 9. If you didn't do it, you probably should. It's good practice. We asked questions about it in class and got many questions cleared up. We then basically reviewed of what we learned yesterday, and elaborated more on each subject. We went over single replacement (p. 13), double replacement (p. 14), Decompostion (p. 15), synthesis (p. 16 &17), and Combustion (p. 17).
Before I describe anything we did today for you, I want you to know 1 trick that is needed every time this happens. Whenever the elements Hydrogen, Oxygen, Nitrogen, Chlorine, Bromine, Iodine, and Florine appears alone in an equation, always put a 2 after it. This is how it is used in nature so it is needed in the writing part too. A way to remember this is HONClBrIF and sound it out.
When going over single replacement, you need to find out which elements are positive or negative ions. If there are 2 positives and 1 negative, then you switch the negative from the one positive to the other. And then of course, balance it out. For example, if you had the formula: ZnS+ O2--->_____. Zn is positive, S is negative, and O is negative. So therefore, on the other side, it would be ZnO2 +S. But then you would have to balance it. So on the right side it would be 2ZnO because on the left it says there are 2 atoms of O (O2). And since I had to change that on the right, on the left it would be 2ZnS, which means on the right I would change it to 2S.
For double replacement, you do the exact same thing as single, except there will be 2 positive ions and 2 negative ions. So you would just swap them and balance them out again.
When doing decomposition, one compound splits up into 2 different ones. For example AB---> A + B. When using elements, an example would be HgO---> Hg + O2. or MgCl2---> Mg + Cl2. Make sure to balance them at the end.
Synthesis is the exact opposite of decomposition. Just put them back together. A + B---> AB. An example using elements would be K + Cl2---> KCl. Mg + O2---> MgO. Make sure that they're balanced at the end.
Finally, we have combustion. This is when there is a carbon atom, hydrogen atom, and oxygen atom all in the same equation. The answer for every single one would be CO2 + H2O no matter what. But the hard part about this is balancing them out. The easiest and smartest way to do this is by using the CHO rules. This is the order of balancing out the equation. Carbon, Hydrogen, and Oxygen. CHO. You won't forget.
Homework:
Page 10 in your journal
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THE NEXT SCRIBER WILL BE........... VIT
Monday, November 22, 2010
11/22/2010
Homework- Do the analysis questions from today's lab. Look over your labs to study for the test.
Thursday, November 18, 2010
11/18/10
Tuesday, November 16, 2010
11.16.10
Monday, November 15, 2010
Monday, November15, 2010
Sunday, November 14, 2010
11-10-10 11-14-10
Tuesday, November 9, 2010
11.9.2010
Monday, November 8, 2010
11.8.10
Wednesday, November 3, 2010
10.4.10
Monday, November 1, 2010
Oct 29, 2010
In class today we learned about naming and writing formulas for ionic compounds. The chart below shows some Polyatomic Ions.
- You have to treat these as One Thing.
Ex) write the formula for elements:
Follow steps for naming and writing formulas for ionic compounds.
1)Find the name of each element
2)Write metal first
- If the first elements are in the transition column; Sn, Pb and D-block elements; then, you use roman numerals in the name of an ionic compound.
Ex)
3) Write non-metal next
- For step 3, the non-metal ends with – ide.
Ex) carbon→carbide - When you have a polyatomic ion you write the given names of them.
Ex) CaCO → calcium carbonate
Upcoming event!
We have Quizzes on Monday through Wednesday! Prepare for these quizzes!.
Wednesday, October 13, 2010
10.13.10
Wednesday, October 6, 2010
October 6, 2010
In class today we learned more about how to find the electron configuration of a nuetral atom. The point of electron configuration is to find the location of the electron.
Shapes of Orbitals
There are four different shapes of orbitals
1) S-one orientation-holds 2 electrons
2)P-three orientations-holds 6 electrons
3)D-five orientations-holds 10 electrons
4)F-seven orientations-holds 14 electrons
The S block always starts as 1S
The P block always starts with 2P
The D block always starts with 3D
The F block always starts with 4F
EXAMPLE 1: If the electron configuration of a neutral atom is 1s2 2s2 2p6 3s2 3p6 then....
a)How many electrons does it have?
18 electrons
(there are two ways in how to find this)
- Add all of the second numbers together (2+2+6+2+6)
- Look at the last electron configuration, which is 3p6, and find it on your periodic table.
18 protons
(Since this is a neutral atom, the electrons and the protons are the same amount)
c)Write the symbol for this atom
Ar
(You can find this on your periodic table)
EXAMPLE 2: Lets say you need to write the electron configuration of Bi (Bismuth). You have to start with 1s2 and end with 6p3(which is where bismuth is located) The way to find write the in between atoms is to read the periodic table from left to right.
1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p6 6s2 4f14 5d10 6p2.
Orbital Diagram
Each half arrow represents how many atoms are in that row.
ALWAYS PUT ONE HALF ARROW FIRST IN EACH BOX BEFORE PUTTING THE SECOND HALF ARROW IN IT.
Ionic Electron Configuration
To write the ionic electron configuration is same as usual. Except for example if they want you to write the electron configuration of O-2, then you have to find where O is, which is 2p4, and go forward 2 because you are gaining 2 more electrons, which is 2p6 and is the atom Ne (Neon)
IN CLASS
We did pages 6, 7 and some of 11 of electron configuration.
REMINDERS
Webassigns are due on Friday. Test is on Friday.
HOMEWORK
Page 8 of electron configuration.
Sunday, October 3, 2010
October 1, 2010
Proton- It has a positive charge and its location is in the nucleus (Remember Proton is Positive)
Neutron- Neutral, it has no charge. Its location is in the nucleus as well.
Electron- Located outside the nucleus. They have a negative charge
We also learned some stuff that has to do with the PERIODIC TABLE.
-The number located above the element's symbol is the atomic number. It represents the number of protons
-The number below the symbol is the atomic mass. That stands for the number of protons PLUS the number of neutrons.
*An atom will usually have the same number of protons and electrons. When those numbers are the same, it has no charge. The only way an atom can get a positive or negative charge is by losing or gaining electrons.
EXAMPLE:
Oxygen's atomic number is 8. Therefore it has 8 protons as well as 8 neutrons. If oxygen were to GAIN 2 electrons(making its total 10 electrons), then it would have a -2 ion(charge) because it has two more electrons than protons. On the other hand, if it were to LOSE two electrons (making its total electrons be 6), then it would have a +2 ion because it has two more protons.
ATOMIC MODELS:
We learned some stuff about orbitals and relative energy and other stuff with Bohr's model, but I did not quite undestand much of that thus, I would explain it poorly. Please be sure to ask Mr. Paek about that stuff.
FIREWORKS LAB:
The purpose was to observe the recations of 7 different salts when they were exposed to fire.
PRE LAB: When electrons drop down an energy level, they give off a specific amount of energy. The energy hits our eyes, excities our neurons, and then we see color.
QUESTION: What does the term "electrons becoming excited" mean?
ANSWER: Energy is added to the electrons so they jump energy levels.
Materials: 7 salts, sticks, water, Bunsen Burner.
Procedure: 1.First we wet the stick a bit in the water
2. Then we dipped it in the salt
3. We placed it over the Bunsen Burner (while it was lit) and observed the reaction
4. Then recorded it in our table
Results:
- Li+(Lithium) Gave off a hot pink color
- Na+(Sodium) Gave off a orange color that looked like fire
- K N O3 Gave off a dull green
- K Cl Gave off a dull purple
- Sr2+ (Strontium) Was red orange
- Cu(Copper) gave off a very dull green (almost white looking)
And Cu2+ was an emerald green
At the end we has three "mystery salts" and had to figure out which ones they were based on the results of the colors we got.
Postlab:
Why did each metal salt give off a different color? That's because they had different numbers of electrons and they each went to different energy levels.
NEXT SCRIBEPOST WILL BE: Zak